Question

How to convet decimal number base-12 number in Java

Answer 1

public class DecimalToBase12 {

    // Converts a decimal number to base-12 and returns it as a string
    public static String decimalToBase12(int decimalNumber) {
        if (decimalNumber == 0) return "0";

        StringBuilder base12 = new StringBuilder();
        final char[] digits = "0123456789AB".toCharArray(); // Base-12 digits (A = 10, B = 11)

        while (decimalNumber > 0) {
            int remainder = decimalNumber % 12;
            base12.append(digits[remainder]);
            decimalNumber /= 12;
        }

        // Reverse to get the correct order
        return base12.reverse().toString();
    }

    public static void main(String[] args) {
        int decimalNumber = 100;
        String base12Number = decimalToBase12(decimalNumber);

        System.out.println("Base-12 representation: " + base12Number);

        decimalNumber = 19621;
        base12Number = decimalToBase12(decimalNumber);

        System.out.println("Base-12 representation: " + base12Number);
    }
}


/*
run:

Base-12 representation: 84
Base-12 representation: B431

*/

 

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