Question

How to convet decimal number base-12 number in Swift

Answer 1

import Foundation

// Converts a decimal number to base-12 and returns it as a string
func decimalToBase12(_ decimalNumber: Int) -> String {
    if decimalNumber == 0 {
        return "0"
    }

    let digits = Array("0123456789AB") // Base-12 digits (A = 10, B = 11)
    var num = decimalNumber
    var base12: [Character] = []

    while num > 0 {
        let remainder = num % 12
        base12.append(digits[remainder])
        num /= 12
    }

    // Reverse to get the correct order
    return String(base12.reversed())
}

let decimalNumber1 = 100
let base12Number1 = decimalToBase12(decimalNumber1)
print("Base-12 representation: \(base12Number1)")

let decimalNumber2 = 19621
let base12Number2 = decimalToBase12(decimalNumber2)
print("Base-12 representation: \(base12Number2)")



/*
run:

Base-12 representation: 84
Base-12 representation: B431

*/

 

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