Question

How to convet decimal number base-12 number in Go

Answer 1

package main

import (
    "fmt"
    "strings"
)

// Converts a decimal number to base-12 and returns it as a string
func decimalToBase12(decimalNumber int) string {
    if decimalNumber == 0 {
        return "0"
    }

    digits := "0123456789AB" // Base-12 digits (A = 10, B = 11)
    var base12 []string

    for decimalNumber > 0 {
        remainder := decimalNumber % 12
        base12 = append(base12, string(digits[remainder]))
        decimalNumber /= 12
    }

    // Reverse to get the correct order
    for i, j := 0, len(base12)-1; i < j; i, j = i+1, j-1 {
        base12[i], base12[j] = base12[j], base12[i]
    }

    return strings.Join(base12, "")
}

func main() {
    decimalNumber := 100
    base12Number := decimalToBase12(decimalNumber)
    fmt.Printf("Base-12 representation: %s\n", base12Number)

    decimalNumber = 19621
    base12Number = decimalToBase12(decimalNumber)
    fmt.Printf("Base-12 representation: %s\n", base12Number)
}


/*
run:

Base-12 representation: 84
Base-12 representation: B431

*/

 

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