Question

How to convet decimal number base-12 number in C

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// Converts a decimal number to its base-12 representation
char* decimalToBase12(int decimalNumber) {
    if (decimalNumber == 0) {
        // Special case for zero
        char* zero = (char*)malloc(2);
        strcpy(zero, "0");
    }

    const char digits[] = "0123456789AB"; // Base-12 digits (A = 10, B = 11)
    char temp[64]; // Temporary buffer to build the number in reverse
    int index = 0;

    while (decimalNumber > 0) {
        int remainder = decimalNumber % 12;
        temp[index++] = digits[remainder];
        decimalNumber /= 12;
    }

    // Reverse the string to get the correct order
    char* base12 = (char*)malloc(index + 1);
    for (int i = 0; i < index; ++i) {
        base12[i] = temp[index - i - 1];
    }
    base12[index] = '\0';

    return base12;
}

int main() {
    int decimalNumber = 100;
    char* base12Number = decimalToBase12(decimalNumber);
    printf("Base-12 representation: %s\n", base12Number);
    free(base12Number); 

    decimalNumber = 19621;
    base12Number = decimalToBase12(decimalNumber);
    printf("Base-12 representation: %s\n", base12Number);
    free(base12Number); 

    return 0;
}


/*
run:

Base-12 representation: 84
Base-12 representation: B431

*/

 

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