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How to find the position of the first set bit (1-bit) of a number in Java

1 Answer

0 votes
public class FirstSetBit {

    // Function to find the position of the first set bit
    public static int findFirstSetBitPosition(int num) {
        // Edge case: If the number is 0, there are no set bits
        if (num == 0) {
            return 0; // Return 0 to indicate no set bit
        }

        // num & -num isolates the lowest set bit.
        // log2(...) gives the zero-based index of that bit.

        return (int)(Math.log(num & -num) / Math.log(2));
    }

    public static void main(String[] args) {
        int num = 4224; // 0001 0000 1000 0000

        // Find and display the position of the first set bit
        int position = findFirstSetBitPosition(num);
        if (position == 0) {
            System.out.println("The number has no set bits (it's 0).");
        } else {
            System.out.println("The position of the first set bit is: " + position);
        }
    }
}



/*
run:

The position of the first set bit is: 7

*/

 



answered Sep 4, 2025 by avibootz
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