Question

How to check if an integer contains an even or odd number of bits set in Java

Answer 1

public class Program {
    public static void main(String[] args) {
        int num = 42; // 0010 1010
        
        int result = Integer.bitCount(num) % 2;
        
        System.out.println("0 = even number of bits set");
        System.out.println("1 = odd number of bits set");
        
        System.out.println("result: " + result);
    }
}



/*
run:

0 = even number of bits set
1 = odd number of bits set
result: 1

*/

 

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