How to find the position of the first set bit (1-bit) of a number in Swift

1 Answer

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import Foundation

// Function to find the position of the first set bit
func findFirstSetBitPosition(_ num: Int) -> Int {
    // Edge case: If the number is 0, there are no set bits
    if num == 0 {
        return 0 // Return 0 to indicate no set bit
    }

    /*
     num & -num isolates the lowest set bit.
     log2(...) gives the zero-based index of that bit.
    */
    return Int(log2(Double(num & -num)))
}

func main() {
    let num = 4224 // 0001 0000 1000 0000

    // Find and display the position of the first set bit
    let position = findFirstSetBitPosition(num)
    if position == 0 {
        print("The number has no set bits (it's 0).")
    } else {
        print("The position of the first set bit is: \(position)")
    }
}

main()



/*
run:

The position of the first set bit is: 7

*/

 



answered Sep 4, 2025 by avibootz
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