How to pass to a function any number of arguments in C#

1 Answer

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using System;

class Program
{
    static void Main()
    {
        // Calling the method with different numbers of arguments
        PrintNumbers(1, 2, 3, 4, 5);
        PrintNumbers(6, 7, 8);
    }

    // Method that accepts any number of integer arguments
    static void PrintNumbers(params int[] arr)
    {
        foreach (int number in arr) {
            Console.Write(number + " ");
        }
        Console.WriteLine();
    }
}

 
  
/*
run:
    
1 2 3 4 5 
6 7 8 
     
*/

 



answered Jan 23, 2025 by avibootz

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