How to pass to a function any number of arguments in TypeScript

1 Answer

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function PrintAll(...args: any[]) {
  console.log(args); // args is an array containing all arguments
  console.log(args[0]);
}
  
PrintAll(1, 2, 3, 4); 
PrintAll('a', 'b', 'c', 'd', 'e'); 
  
  
  
/*
run:
  
[1, 2, 3, 4] 
1 
["a", "b", "c", "d", "e"] 
"a" 
  
*/


/*
run:

(4) [1, 2, 3, 4]
1
(5) ["a", "b", "c", "d", "e"]
a

*/

 



answered Jan 23, 2025 by avibootz
edited Jan 23, 2025 by avibootz

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