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How to pass to a function any number of arguments in PHP

3 Answers

0 votes
function sum(...$numbers) {
    return array_sum($numbers);
}

echo sum(1, 2, 3, 4) . "\n"; 
echo sum(6, 7, 8) . "\n"; 



/*
run:

10
21

*/

 



answered Jan 23, 2025 by avibootz
0 votes
function sum() {
    $numbers = func_get_args();
    
    return array_sum($numbers);
}

echo sum(1, 2, 3, 4) . "\n"; 
echo sum(6, 7, 8) . "\n"; 



/*
run:

10
21

*/

 



answered Jan 23, 2025 by avibootz
0 votes
function sum() {
    $total = 0;
    
    for ($i = 0; $i < func_num_args(); $i++) {
        $total += func_get_arg($i);
    }
    
    return $total;
}

echo sum(1, 2, 3, 4) . "\n"; 
echo sum(6, 7, 8) . "\n"; 



/*
run:

10
21

*/

 



answered Jan 23, 2025 by avibootz

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