Question

How to check if a number is curious number (sum of the factorials of each digit equal to itself) in Node.js

Answer 1

function factorial(n) {
    return (n == 1 || n == 0) ? 1 : n * factorial(n - 1);
}


function sumFactorialDigits(num) {
    let sum = 0;
    
    while (num != 0) {
        sum += factorial(Math.trunc(num % 10));
        num = Math.trunc(num / 10);
    }
    
    return sum;
}

let number = 145;

if (number == sumFactorialDigits(number)) {
    console.log("Curious number");
}
else {
    console.log("Not curious number");
}





/*
run:
   
Curious number
   
*/

 

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