Question

How to check if a number is curious number (sum of the factorials of each digit equal to itself) in C#

Answer 1

using System;

public class Program
{
	private static int factorial(int n) {
		return (n == 1 || n == 0) ? 1 : n * factorial(n - 1);
	}

	private static int sumFactorialDigits(int num) {
		int sum = 0;

		while (num != 0) {
			sum += factorial(num % 10);
			num /= 10;
		}

		return sum;
	}

	public static void Main(string[] args)
	{
		int number = 145;

		if (number == sumFactorialDigits(number)) {
			Console.Write("Curious number");
		}
		else {
			Console.Write("Not curious number");
		}
	}
}





/*
run:
  
Curious number
  
*/

 

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