Question

How to check if a number is curious number (sum of the factorials of each digit equal to itself) in Java

Answer 1

public class MyClass {
    private static int factorial(int n) {
    	return (n == 1 || n == 0) ? 1 : n * factorial(n - 1);
    }
    
    private static int sumFactorialDigits(int num) {
    	int sum = 0;
    
    	while (num != 0) {
    		sum += factorial(num % 10);
    		num /= 10;
    	}
    
    	return sum;
    }
    
    public static void main(String args[]) {
      	int number = 145;

	    if (number == sumFactorialDigits(number)) {
		    System.out.print("Curious number");
	    }
	    else {
		    System.out.print("Not curious number");
	    }
    }
}





/*
run:
  
Curious number
  
*/

 

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