How top use exception handling in Python

4 Answers

0 votes
try:
    a = 12
    print(a//0)
except:
    print("Error")
    
    
    
'''
run:

Error

'''

 



answered Dec 11, 2020 by avibootz
0 votes
try:
    a = 12
    print(a//2)
except:
    print("Error")
else:
    print("No Errors")
    
    
    
'''
run:

6
No Errors

'''

 



answered Dec 11, 2020 by avibootz
0 votes
try:
    a = 12
    print(a//0)
except:
    print("Error")
finally:
    print("finally")
    
    
    
'''
run:

Error
finally

'''

 



answered Dec 11, 2020 by avibootz
0 votes
try:
    a = 12
    print(a//2)
except:
    print("Error")
else:
    print("No Errors")
finally:
    print("finally")
    
    
     
     
'''
run:
 
6
No Errors
finally
 
'''

 



answered Dec 11, 2020 by avibootz

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