Question

How to use exception handling with open file in Python

Answer 1

try:
    f = open('d:\dataaa.txt')
    s = f.readline()
except IOError as e:
    error_no, strerror = e.args
    print("I/O error number:{0} - {1}".format(error_no, strerror))


'''
run:

I/O error number:2 - No such file or directory

'''

 

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Answer 2

try:
    f = open('d:\dataaa.txt')
    s = f.readline()
except IOError as e:
    print(e)

'''
run:

[Errno 2] No such file or directory: 'd:\\dataaa.txt'

'''

 

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