Question

How to input a number with exception handling in Python

Answer 1

while True:
    try:
        n = input("Enter a number: ")
        n = int(n)
        break
    except ValueError:
        print("Not valid number! Try again")

print("Success, you entered the number:", n)


'''
run:

Enter a number: aa
Not valid number! Try again
Enter a number: 21
Success, you entered the number: 21

'''

 

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