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How to calculate the length of legB and hypotenuse of a right-angle triangle with a given perimeter and legA in Java

1 Answer

0 votes
public class RightTriangle {
    public static void main(String[] args) {
        double perimeter = 120;
        double legA = 20;

        // From perimeter: a + b + c = P
        // From Pythagoras: c = sqrt(a^2 + b^2)
        // Substitute c into perimeter equation: a + b + sqrt(a^2 + b^2) = P
        // Solve for legB
        double legB = (Math.pow(perimeter - legA, 2) - Math.pow(legA, 2)) 
                      / (2 * (perimeter - legA));

        if (legB <= 0) {
            System.err.println("No valid right triangle exists with these values.");
            return;
        }

        double hypotenuse = Math.sqrt(legA * legA + legB * legB);

        System.out.printf("Leg a: %.3f%n", legA);
        System.out.printf("Leg b: %.3f%n", legB);
        System.out.printf("Hypotenuse c: %.3f%n", hypotenuse);
    }
}



/*
run:
  
Leg a: 20.000
Leg b: 48.000
Hypotenuse c: 52.000
  
*/

 



answered Nov 17, 2025 by avibootz

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