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How to calculate the length of legB and hypotenuse of a right-angle triangle with a given perimeter and legA in Pascal

1 Answer

0 votes
program RightTriangle;

uses
  Math;  { for Sqrt and Power }

var
  perimeter, legA, legB, hypotenuse: Real;

begin
  perimeter := 120;
  legA := 20;

  { From perimeter: a + b + c = P }
  { From Pythagoras: c = sqrt(a^2 + b^2) }
  { Substitute c into perimeter equation: a + b + sqrt(a^2 + b^2) = P }
  { Solve for legB }
  legB := (Power(perimeter - legA, 2) - Power(legA, 2)) / (2 * (perimeter - legA));

  if legB <= 0 then
  begin
    WriteLn('No valid right triangle exists with these values.');
    Halt(1);
  end;

  hypotenuse := Sqrt(legA * legA + legB * legB);

  { Output with formatting }
  WriteLn('Leg a: ', legA:0:3);
  WriteLn('Leg b: ', legB:0:3);
  WriteLn('Hypotenuse: ', hypotenuse:0:3);
end.



(*
run:

Leg a: 20.000
Leg b: 48.000
Hypotenuse: 52.000

*)

 



answered Nov 17, 2025 by avibootz

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