How to generate a random hexadecimal string in C#

1 Answer

0 votes
using System;

class RandomHexGenerator
{
    static string GenerateHex(int length) {
        const string hexChars = "0123456789ABCDEF";
        Random rand = new Random();
        char[] hexArray = new char[length];

        for (int i = 0; i < length; i++) {
            int index = rand.Next(16); // Random number between 0 and 15
            hexArray[i] = hexChars[index];
        }

        return new string(hexArray);
    }

    static void Main()
    {
        int length = 8; // Length of the hex string
        string hexNumber = GenerateHex(length);
        
        Console.WriteLine("Random Hexadecimal Number: " + hexNumber);
    }
}


/*
run:

Random Hexadecimal Number: 6121D168

*/

 



answered Sep 18, 2025 by avibootz

Related questions

...