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How to generate a secure random hexadecimal string in Java

1 Answer

0 votes
import java.security.SecureRandom; 
 
public class RandomHexGenerator {  
   public static void main(String[] args) {  
      String hexstr = generateHex(8); 
       
      System.out.println("Random hexadecimal: " + hexstr);  
   }  
   public static String generateHex(int length) {  
      SecureRandom random = new SecureRandom();  
      StringBuilder hexstring = new StringBuilder();  
       
      for (int i = 0; i < length; i++) {  
         int rndvalue = random.nextInt(16);  
          
         hexstring.append(Integer.toHexString(rndvalue));  
      }  
       
      return hexstring.toString();  
   }  
}
 
 
/*
run:
 
Random hexadecimal: f23dcd9e
 
*/

 



answered Sep 19, 2025 by avibootz
edited Sep 19, 2025 by avibootz
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