How to set specific bits in a char with Swift

1 Answer

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import Foundation

func printBinary(_ ch: Int) {
    let binary = String(format: "%08d", Int(String(ch & 0xFF, radix: 2))!)
    print(binary)
}

var ch = 0
ch |= (1 << 7) // Set the 7th bit (128)
ch |= (1 << 3) // Set the 3rd bit (8)

printBinary(ch)           // Binary: 10001000
print("Value: \(ch)")     // Decimal: 136



/*
run:

10001000
Value: 136

*/

 



answered Jul 31, 2025 by avibootz
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