Question

How to sum the proper divisors of a number in Rust

Answer 1

fn sum_number_proper_divisors(num: u32) -> u32 {
    let mut sum = 0;

    for i in 1..=num / 2 {
        if num % i == 0 {
            print!("{}, ", i);
            sum += i;
        }
    }

    sum
}

fn main() {
    let sum = sum_number_proper_divisors(220);
    
    println!("\n{}", sum);
}



    
/*
run:

1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110, 
284
   
*/

 

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