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How to sum the proper divisors of a number in Go

1 Answer

0 votes
package main

import (
    "fmt"
)

func SumNumberProperDivisors(num uint) uint {
    var sum uint = 0
    
    for i := uint(1); i <= num/2; i++ {
        if num%i == 0 {
            fmt.Printf("%d, ", i)
            sum += i
        }
    }
    
    return sum
}

func main() {
    sum := SumNumberProperDivisors(220)
    
    fmt.Printf("\n%d\n", sum)
}



/*
run:
1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110, 
284

*/

 



answered Aug 8, 2025 by avibootz

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