Question

How to get the lower 8 bits of an int in Kotlin

Answer 1

fun printBinary(n: Int, width: Int): String {
    val binary = n.toString(2)

    return "0".repeat(width - binary.length) + binary
}

fun main() {
    val n = 1957

    // Print 16-bit binary representation
    println(printBinary(n, 16))

    // Extract low 8 bits
    val low8bits = n and 0xFF
    println(printBinary(low8bits, 16)) // Also padded to 16 bits
}


 
  
/*
run:
 
0000011110100101
0000000010100101

*/

 

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