Question

How to get the lower 8 bits of an int in Python

Answer 1

def print_binary(n, width):
    binary = bin(n)[2:]  # Remove '0b' prefix
    return binary.zfill(width)


n = 1957

# Print 16-bit binary representation
print(print_binary(n, 16))

# Extract low 8 bits
low8bits = n & 0xFF
print(print_binary(low8bits, 16))  # Also padded to 16 bits


  
'''
run:
  
0000011110100101
0000000010100101
  
'''

 

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