Question

How to check if an integer contains an even or odd number of bits set in Node.js

Answer 1

const num = 45; // 0010 1101
 
// Convert to binary string and count '1's
const bitCount = num.toString(2).split('').filter(ch => ch === '1').length;
const result = bitCount % 2;
 
console.log("0 = even number of bits set");
console.log("1 = odd number of bits set");
console.log("result: " + result);
 
  
     
/*
run:
      
0 = even number of bits set
1 = odd number of bits set
result: 0
       
*/

 

 

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Answer 2

const num = 45; // 0010 1101
 
const result = num.toString(2)
                  .split('')
                  .reduce((parity, bit) => parity ^ bit, 0)
 
console.log("0 = even number of bits set");
console.log("1 = odd number of bits set");
console.log("result: " + result);

  
     
/*
run:
      
0 = even number of bits set
1 = odd number of bits set
result: 0
       
*/

 

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