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How to sort a numeric array in descending order with Kotlin

3 Answers

0 votes
fun main() {
    val array = arrayOf(5, 9, 3, 0, 8, 1, 2, 7, 4, 6)

	val sortedArray = array.sortedArrayDescending()
	
    println(sortedArray.joinToString(", "))

}
 
 
    
/*
run:
 
9, 8, 7, 6, 5, 4, 3, 2, 1, 0
  
*/

 



answered Feb 26, 2025 by avibootz
0 votes
fun main() {
    val array = arrayOf(5, 9, 3, 0, 8, 1, 2, 7, 4, 6)

	array.sortDescending()
	
    println(array.joinToString(", "))

}
 
 
    
/*
run:
 
9, 8, 7, 6, 5, 4, 3, 2, 1, 0
  
*/

 



answered Feb 26, 2025 by avibootz
0 votes
fun main() {
    val array = arrayOf(5, 9, 3, 0, 8, 1, 2, 7, 4, 6)

	val sortedArray = array.sortedByDescending { it }
	
    println(sortedArray.joinToString(", "))

}
 
 
    
/*
run:
 
9, 8, 7, 6, 5, 4, 3, 2, 1, 0
  
*/

 



answered Feb 26, 2025 by avibootz

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