Question

How to sort a numeric array in descending order with Scala

Answer 1

val array = Array(5, 9, 3, 0, 8, 1, 2, 7, 4, 6)

val sortedArray = array.sortWith(_ > _)

println(sortedArray.mkString(", "))



/*
run:

9, 8, 7, 6, 5, 4, 3, 2, 1, 0
 
*/

 

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Answer 2

val array = Array(5, 9, 3, 0, 8, 1, 2, 7, 4, 6)

val sortedArray = array.sorted(Ordering[Int].reverse)

println(sortedArray.mkString(", "))



/*
run:

9, 8, 7, 6, 5, 4, 3, 2, 1, 0
 
*/

 

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Answer 3

val array = Array(5, 9, 3, 0, 8, 1, 2, 7, 4, 6)

val sortedArray = array.sortBy(-_)

println(sortedArray.mkString(", "))



/*
run:

9, 8, 7, 6, 5, 4, 3, 2, 1, 0
 
*/

 

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