Question

How to use the function Math.pow() to get the base to the exponent power in JavaScript

Answer 1

document.write("Math.pow(3, 2) = " + Math.pow(3, 2) + "<br />");
document.write("Math.pow(3, 3) = " + Math.pow(3, 3) + "<br />");
document.write("Math.pow(2, 10) = " + Math.pow(2, 10) + "<br />");
document.write("Math.pow(-7, 0.5) = " + Math.pow(-7, 0.5) + "<br />");
document.write("Math.pow(-7, 1/3) = " + Math.pow(-7, 1/3) + "<br />");
document.write("Math.pow(-7, 2) = " + Math.pow(-7, 2) + "<br />");
document.write("Math.pow(-7, 3) = " + Math.pow(-7, 3) + "<br />");
document.write("Math.pow(-7, -2) = " + Math.pow(-7, -2) + "<br />");
document.write("Math.pow(8, -1/3) = " + Math.pow(8, -1/3) + "<br />");
document.write("Math.pow(4, 0.5) = " + Math.pow(4, 0.5) + "<br />");
document.write("Math.pow(8, 1/3) = " + Math.pow(8, 1/3) + "<br />");
document.write("Math.pow(2, 0.5) = " + Math.pow(2, 0.5) + "<br />");
document.write("Math.pow(2, 1/3) = " + Math.pow(2, 2/3) + "<br />");
document.write("Math.pow(9, 0.5) = " + Math.pow(9, 0.5) + "<br />");

 
/*
run

Math.pow(3, 2) = 9
Math.pow(3, 3) = 27
Math.pow(2, 10) = 1024
Math.pow(-7, 0.5) = NaN
Math.pow(-7, 1/3) = NaN
Math.pow(-7, 2) = 49
Math.pow(-7, 3) = -343
Math.pow(-7, -2) = 0.02040816326530612
Math.pow(8, -1/3) = 0.5
Math.pow(4, 0.5) = 2
Math.pow(8, 1/3) = 2
Math.pow(2, 0.5) = 1.4142135623730951
Math.pow(2, 1/3) = 1.5874010519681993
Math.pow(9, 0.5) = 3
 
*/

 

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