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How to use pow() function to calculate a value of base raised to the power exponent in C++

1 Answer

0 votes
#include <iostream>
#include <cmath>

using namespace std;

int main()
{
	cout << "pow(5.0, 3.0) = " << pow(5.0, 3.0) << endl;
	cout << "pow(3.14, 10.0) = " << pow(3.14, 10.0) << endl;
	cout << "pow(31.15, 1.43) = " << pow(31.15, 1.43) << endl;
	cout << "pow(4, 0.5) = " << pow(4, 0.5) << endl;
	cout << "pow(-3, -2) = " << pow(-3, -2) << endl;

	return 0;

}

/*
run:

pow(5.0, 3.0) = 125
pow(3.14, 10.0) = 93174.4
pow(31.15, 1.43) = 136.661
pow(4, 0.5) = 2
pow(-3, -2) = 0.111111

*/

 



answered Mar 28, 2016 by avibootz
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