Question

How to count the number of non-overlapping instances of substring in a string in TypeScript

Answer 1

function countNonOverlappingOccurrences(str: string, substr: string) {
    if (substr === "") return 0;
 
    let count: number = 0;
    let offset: number = str.indexOf(substr);
 
    while (offset !== -1) {
        count++;
        offset = str.indexOf(substr, offset + substr.length);
    }
 
    return count;
}
 
const s: string = "phptypescript php c++ python php phphp";
 
console.log(countNonOverlappingOccurrences(s, "php"));
 
 
    
/*
run:
    
4
 
*/

 

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Answer 2

function countNonOverlappingOccurrences(str: string, substr: string) {
    return (str.length - str.replace(new RegExp(substr, "gi"), "").length) / substr.length;
}
 
const s: string = "phptypescript php c++ python php phphp";
 
console.log(countNonOverlappingOccurrences(s, "php"));
 
 
    
/*
run:
    
4
 
*/

 

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