Question

How to count the number of non-overlapping instances of substring in a string in Python

Answer 1

def countOccurrences(s, substr):
    count = offset = 0
     
    for i in range(len(s)):
        i = s.find(substring, offset)
        if (i > 0):
            offset = i + len(substring)
            count += 1
        else:
            break    
        
    return count;

s = 'java php c c++ python php phphp'
substring = 'php'

print(countOccurrences(s, substring))
    
    
    
'''
run:
    
3
  
'''

 

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Answer 2

s = 'java php c c++ python php phphp'
substring = 'php'

print(s.count(substring))
    
    
    
'''
run:
    
3
  
'''

 

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