Question

How to check if a grid is a valid word square (same words horizontally and vertically) in JavaScript

Answer 1

const validWordSquares = (grid = []) => {
    for (let i = 0; i < grid.length; i++) {
        for (let j = 0; j < grid[i].length; j++) {
            if (i >= grid.length || j >= grid.length || j >= grid[i].length || i >= grid[j].length) {
                return false;
            }
            if (grid[i][j] !== grid[j][i]) {
                return false;
            }
        }
    }
     
    return true;
};
 
const grid = [
   "abcde",
   "bvqz",
   "cqm",
   "dz",
   "e"
];
 
console.log(validWordSquares(grid));
 
 
 
/*
run:
 
true
 
*/

 

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