Question

How to check if a grid is a valid word square (same words horizontally and vertically) in TypeScript

Answer 1

const validWordSquares = (grid: string[]) => {
    for (let i: number = 0; i < grid.length; i++) {
        for (let j: number = 0; j < grid[i].length; j++) {
            if (i >= grid.length || j >= grid.length || j >= grid[i].length || i >= grid[j].length) {
                return false;
            }
            if (grid[i][j] !== grid[j][i]) {
                return false;
            }
        }
    }
    
    return true;
};

const grid: string[] = [
    "abcde",
    "bvqz",
    "cqm",
    "dz",
    "e"
];

console.log(validWordSquares(grid));



/*
run:

true

*/

 

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