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How to implement method overloading based on the order of arguments in Java

1 Answer

0 votes
public class MyClass {
    public static int max(int num1, int num2) {
        System.out.print("max(int num1, int num2): ");
        
        if (num1 > num2)
            return num1;
        else
            return num2;
    }
    
    public static float max(int num1, float num2) {
        System.out.print("max(int num1, float num2): ");
        
        if (num1 > num2)
            return num1;
        else
            return num2;
    }
    
    public static float max(float num1, int num2) {
        System.out.print("max(float num1, int num2): ");
        
        if (num1 > num2)
            return num1;
        else
            return num2;
    }

    public static void main(String args[]) {
       System.out.println(max(5, 9));
       
       System.out.println(max(3, 6.79F));
       
       System.out.println(max(23.2F, 300));
    }
}
 
 
 
 
 
/*
run:
 
max(int num1, int num2): 9
max(int num1, float num2): 6.79
max(float num1, int num2): 300.0
 
*/

 



answered Jan 27, 2024 by avibootz
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