Question

How to implement method overloading based on the types of arguments in Java

Answer 1

public class MyClass {
    static double sum(int a, int b) {
        double sm = 0;

        sm = a + b;

        return sm;
    }

    static double sum(int a, float b) {
        double sm = 0;

        sm = a + b;

        return sm;
    }

    static double sum(int a, double b) {
        double sm = 0;

        sm = a + b;

        return sm;
    }
    
    public static void main(String args[]) {
        double result = sum(8, 7);
        System.out.println("Sum = " + result);

        result = sum(5, 3.14F);
        System.out.println("Sum = " + result);

        result = sum(56, 73.958);
        System.out.println("Sum = " + result);
    }
}




/*
run:
  
Sum = 15.0
Sum = 8.140000343322754
Sum = 129.958
   
*/

 

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