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How to check if a matrix is Toeplitz or not in JavaScript

1 Answer

0 votes
// A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same elements
 
function isToeplitz(matrix) {
    const rows = matrix.length;
    const cols = matrix[0].length;
     
    for (let i = 1; i < rows; i++) {
        for (let j = 1; j < cols; j++) {
            console.log(i + " " + j + " - " + matrix[i][j] + " : " + matrix[i - 1][j - 1]);
            if (matrix[i][j] != matrix[i - 1][j - 1]) {
                return false;
            }
        }
        console.log("-----------");
    }
     
    return true;
}
         
const matrix = [
    [2, 7, 9, 8], 
    [4, 2, 7, 9], 
    [3, 4, 2, 7], 
    [0, 3, 4, 2], 
    [6, 0, 3, 4]];
     
if (isToeplitz(matrix)) {
    console.log("Matrix is a Toeplitz");
}
else {
    console.log("Matrix is not a Toeplitz");
}
 
  
  
/*
run:
     
1 1 - 2 : 2
1 2 - 7 : 7
1 3 - 9 : 9
-----------
2 1 - 4 : 4
2 2 - 2 : 2
2 3 - 7 : 7
-----------
3 1 - 3 : 3
3 2 - 4 : 4
3 3 - 2 : 2
-----------
4 1 - 0 : 0
4 2 - 3 : 3
4 3 - 4 : 4
-----------
Matrix is a Toeplitz
         
*/

 



answered Jan 23, 2024 by avibootz
edited Jan 31, 2025 by avibootz

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