Question

How to find the most frequent word in an array of strings with TypeScript

Answer 1

function mostFrequentWord(words: string[]) {
    let frequency: number = 0;
    const size: number = words.length;
    let frequent_word: string = "";
    
    for (let i: number = 0; i < size; i++) {
        let count: number = 1;
        for (let j: number = i + 1; j < size; j++) {
            if (words[j]== words[i]) {
                count++;
            }
        }
        if (count >= frequency) {
            frequent_word = words[i];
            frequency = count;
        }
    }
    return frequent_word;
}

const arr: string[] = ["java", "c++", "c", "c#", "c", "go", "php", "java", "java", "c", "typescript", "php", "c"];

const frequent_word = mostFrequentWord(arr);

console.log(frequent_word);



/*
run:
  
"c" 
  
*/

 

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