Question

How to find the most frequent word in an array of strings with Java

Answer 1

public class MyClass {
    private static void mostFrequentWord(String[] words) {
    	int frequency = 0;
    	int size = words.length;
    	String frequent_word = "";
    
    	for (int i = 0; i < size; i++) {
    		int count = 1;
    		for (int j = i + 1; j < size; j++) {
    			if (words[j].equals(words[i])) {
    				count++;
    			}
    		}
    		if (count >= frequency) {
    			frequent_word = words[i];
    			frequency = count;
    		}
    	}
    
    	System.out.println(frequent_word + ": " + frequency + " times");
    }
    public static void main(String args[]) {
      	String[] arr = {"java", "c++", "c", "c#", "c", "go", "php", "java", "java", "c", "python", "php", "c"};

	    mostFrequentWord(arr);
    }
}






/*
run:
 
c: 4 times
 
*/

 

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Answer 2

public class MyClass {
    private static String mostFrequentWord(String[] words) {
        int frequency = 0;
        int size = words.length;
        String frequent_word = "";
     
        for (int i = 0; i < size; i++) {
            int count = 1;
            for (int j = i + 1; j < size; j++) {
                if (words[j].equals(words[i])) {
                    count++;
                }
            }
            if (count >= frequency) {
                frequent_word = words[i];
                frequency = count;
            }
        }
     
        return frequent_word;
    }
    public static void main(String args[]) {
        String[] arr = {"java", "c++", "c", "c#", "c", "go", "php", "java", "java", "c", "python", "php", "c"};
 
        String frequent_word = mostFrequentWord(arr);
        
        System.out.println(frequent_word);
    }
}
 
 
 
 
 
 
/*
run:
  
c
  
*/

 

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