Question

How to find pythagorean triplet values for which a + b + c <= 25 in C++

Answer 1

#include <iostream>

int main()
{
    const int sum = 25;
     
    for (int a = 1; a <= sum; a++) {
        for (int b = a + 1; b <= sum; b++) {
            for (int c = b + 1; c <= sum; c++) {
                if (a * a + b * b == c * c) {
                    std::cout << "a = " << a << " b = " << b << " c = " << c << "\n";
                }
            }
        }
    }
}
  
  
  
// examples:
 
// (3 ^ 2 = 9) + (4 ^ 2 = 16) = 25 = 5 ^ 2
// (5 ^ 2 = 25) + (12 ^ 2 = 144) = 169 = 13 ^ 2
  
  
  
  
/*
run:
  
a = 3, b = 4, c = 5
a = 5, b = 12, c = 13
a = 6, b = 8, c = 10
a = 7, b = 24, c = 25
a = 8, b = 15, c = 17
a = 9, b = 12, c = 15
a = 12, b = 16, c = 20
a = 15, b = 20, c = 25
  
*/

 

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