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How to find pythagorean triplet for which a + b + c = 1000 in Scala

1 Answer

0 votes
object PythagoreanTriplet extends App {

  // Define the total sum of the Pythagorean triplet (a + b + c = 1000)
  val sum = 1000

  // Loop through possible values for 'a'
  // 'a' is the smallest in the triplet, so only check up to sum/3
  for (a <- 1 to sum / 3) {

    // Loop through possible values for 'b', starting just above 'a'
    // 'b' must be less than 'c', so only go up to sum/2
    for (b <- a + 1 to sum / 2) {

      // Calculate 'c' as the remaining value so that a + b + c = sum
      val c = sum - a - b

      // Check if the triplet (a, b, c) satisfies the Pythagorean condition: a² + b² == c²
      if (a * a + b * b == c * c) {
        println(s"($a^2 = ${a * a}) + ($b^2 = ${b * b}) = $c^2 = ${c * c}")
        println(s"a = $a, b = $b, c = $c")
        println(s"${a + b + c} = $a + $b + $c")
      }
    }
  }
}



/*
run:
 
(200^2 = 40000) + (375^2 = 140625) = 425^2 = 180625
a = 200, b = 375, c = 425
1000 = 200 + 375 + 425
 
*/

 



answered Jul 25, 2025 by avibootz
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