Question

How to split an array into two parts in Java

Answer 1

import java.util.Arrays;
 
public class MyClass
{
    public static void main(String[] args)
    {
        int[] arr = { 1, 2, 3, 4, 5, 6, 7 };
        int size = arr.length;
 
        int[] a = new int[(size + 1) / 2];
        int[] b = new int[size - a.length];
 
        for (int i = 0; i < size; i++) {
            if (i < a.length) {
                a[i] = arr[i];
            }
            else {
                b[i - a.length] = arr[i];
            }
        }
 
        System.out.println(Arrays.toString(a));
        System.out.println(Arrays.toString(b));
    }
}




/*
run:

[1, 2, 3, 4]
[5, 6, 7]

*/

 

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Answer 2

import java.util.Arrays;
 
public class MyClass
{
    public static void main(String[] args)
    {
        int[] arr = { 1, 2, 3, 4, 5, 6, 7 };
        int size = arr.length;
 
        int[] a = new int[(size + 1) / 2];
        int[] b = new int[size - a.length];
 
        System.arraycopy(arr, 0, a, 0, a.length);
        System.arraycopy(arr, a.length, b, 0, b.length);
 
        System.out.println(Arrays.toString(a));
        System.out.println(Arrays.toString(b));
    }
}




/*
run:

[1, 2, 3, 4]
[5, 6, 7]

*/

 

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Answer 3

import java.util.Arrays;
 
public class MyClass
{
    public static void main(String[] args)
    {
        int[] arr = { 1, 2, 3, 4, 5, 6, 7 };
        int size = arr.length;

        int[] a = Arrays.copyOfRange(arr, 0, (size + 1) / 2);
        int[] b = Arrays.copyOfRange(arr, (size + 1) / 2, size);
 
        System.out.println(Arrays.toString(a));
        System.out.println(Arrays.toString(b));
    }
}




/*
run:

[1, 2, 3, 4]
[5, 6, 7]

*/

 

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