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How to split a number N into M random positive parts whose sum is exactly N in Swift

1 Answer

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import Foundation

/*
    Split a number N into M random positive parts that sum to N.
 
    Algorithm (uniform integer composition):
    ----------------------------------------
    1. We want M positive integers p1, p2, ..., pM such that:
           p1 + p2 + ... + pM = N
 
    2. Generate (M - 1) random "cut points" in the range [1, N - 1].
       Example: N = 20, M = 4 → generate 3 cuts, e.g. {3, 11, 17}
       
    3. Sort the cut points.
 
    4. The parts are the differences between consecutive cuts:
         p1 = cut[0]
         p2 = cut[1] - cut[0]
         ...
         pM = N - cut[M-2]
 
    This produces a uniformly random composition of N into M parts.
*/

/*
    Important:
    -----------
    Random cut points must be UNIQUE.
    If two cut points are equal, their difference becomes 0,
    which produces an invalid part.
*/

// Generate M random positive parts summing to N
func splitIntoRandomParts(_ N: Int, _ M: Int) -> [Int] {
    if M <= 0 || N < M {
        fatalError("Invalid N or M: require N >= M >= 1")
    }

    var cuts: [Int] = []
    var used: Set<Int> = []   // ensures uniqueness

    // Generate UNIQUE cut points
    while cuts.count < M - 1 {
        let c = Int.random(in: 1..<N)
        if !used.contains(c) {
            used.insert(c)
            cuts.append(c)
        }
    }

    // Sort the cut points
    cuts.sort()

    // Build the parts
    var parts: [Int] = []
    var prev = 0

    for c in cuts {
        parts.append(c - prev)   // guaranteed >= 1
        prev = c
    }

    parts.append(N - prev)       // last part, also >= 1

    return parts
}

let N = 30
let M = 5

let parts = splitIntoRandomParts(N, M)

print("Splitting N = \(N) into M = \(M) random parts:")
print(parts.map { "\($0)" }.joined(separator: " "))


/*
run:

Splitting N = 30 into M = 5 random parts:
3 10 5 2 10

*/

 



answered Jul 19 by avibootz

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