Question

How to count the number of strictly increasing subarrays in an array with Node.js

Answer 1

function countStrictlyIncreasingSubarrays(arr) {
    const size = arr.length;
    let count = 0;
        
    for (let i = 0; i < size; i++) {
        for (let j = i + 1; j < size; j++) {
            if (arr[j - 1] >= arr[j]) {
                break;
            }
            count++;
            let s = "";                        // for print only
            for (let k = i; k < j + 1; k++) {  // for print only
                s = s + arr[k] + " ";          // for print only
            }                                  // for print only
            console.log(s);                    // for print only
        }
    }
    return count;
}
        
const arr = [1, 3, 4, 0, 7, 6, 9];
// {1, 3}, {1, 3, 4}, {3, 4}, {0, 7}, {6, 9}
        
console.log(countStrictlyIncreasingSubarrays(arr) + " = Count of strictly increasing subarrays");

      
  
    
      
      
/*
run:
      
1 3 
1 3 4 
3 4 
0 7 
6 9 
5 = Count of strictly increasing subarrays
      
*/

 

 

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