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How to count the number of strictly increasing subarrays in an array with VB.NET

1 Answer

0 votes
Imports System

Public Class Program
    Public Shared Function countStrictlyIncreasingSubarrays(ByVal arr As Integer()) As Integer
        Dim size As Integer = arr.Length
        Dim count As Integer = 0

        For i As Integer = 0 To size - 1

            For j As Integer = i + 1 To size - 1

                If arr(j - 1) >= arr(j) Then
                    Exit For
                End If

                count += 1

                For k As Integer = i To j + 1 - 1  ' for print only 
                    Console.Write(arr(k) & " ")    ' for print only 
                Next                               ' for print only 
                Console.WriteLine()                ' for print only 
            Next
        Next

        Return count
    End Function

    Public Shared Sub Main(ByVal args As String())
        Dim arr As Integer() = New Integer() {1, 3, 4, 0, 7, 5, 9}

        Console.Write(countStrictlyIncreasingSubarrays(arr))

        Console.Write(" = Count of strictly increasing subarrays")
    End Sub
End Class




' run:
'
' 1 3 
' 1 3 4 
' 3 4 
' 0 7 
' 5 9 
' 5 = Count of strictly increasing subarrays
'

 



answered Aug 21, 2022 by avibootz
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