function countStrictlyIncreasingSubarrays(arr : any) {
const size = arr.length;
let count = 0;
for (let i = 0; i < size; i++) {
for (let j = i + 1; j < size; j++) {
if (arr[j - 1] >= arr[j]) {
break;
}
count++;
let s = ""; // for print only
for (let k = i; k < j + 1; k++) { // for print only
s = s + arr[k] + " "; // for print only
} // for print only
console.log(s); // for print only
}
}
return count;
}
const arr:number[] = [1, 3, 4, 0, 7, 2, 9];
// {1, 3}, {1, 3, 4}, {3, 4}, {0, 7}, {2, 9}
console.log(countStrictlyIncreasingSubarrays(arr) + " = Count of strictly increasing subarrays");
/*
run:
"1 3 "
"1 3 4 "
"3 4 "
"0 7 "
"2 9 "
"5 = Count of strictly increasing subarrays"
*/
