Question

How to check if two arrays contain any common elements in Typescript

Answer 1

function containCommonElements(arr1: any, arr2 : any) { 
    return arr1.some(item => arr2.includes(item)) 
} 
   
const arr1 = [22, 26, 12, 19, 18, 99, 81];
const arr2 = [1, 8, 5, 12, 18, 19, 100, 120];

console.log(containCommonElements(arr1, arr2));
   
   
    
    
/*
run:
    
true
  
*/
 

 

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Answer 2

const arr1 = [22, 26, 12, 19, 18, 99, 81];
const arr2 = [1, 8, 5, 12, 18, 19, 100, 120];

console.log(arr1.some(element => { return arr2.includes(element); }));
   
   
    
    
/*
run:
    
true
  
*/
 

 

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Answer 3

const arr1 = [22, 26, 12, 19, 18, 99, 81];
const arr2 = [1, 8, 5, 12, 18, 19, 100, 120];

console.log(arr1.some(r=> arr2.indexOf(r) >= 0));
   
   
    
    
/*
run:
    
true
  
*/
 

 

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