How to find the uncommon elements from two arrays in TypeScript

1 Answer

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const arr1: number[] = [1, 3, 8,  9, 16, 18];
const arr2: number[] = [1, 8, 5, 12, 18, 42, 101, 130];
 
const uncommon_arr1: number[] = arr1.filter(function(obj) { return arr2.indexOf(obj) == -1; });
const uncommon_arr2: number[] = arr2.filter(function(obj) { return arr1.indexOf(obj) == -1; });

const uncommon: number[] = [...uncommon_arr1, ...uncommon_arr2]
         
console.log(uncommon);
   
   
   
/*
run:
   
[3, 9, 16, 5, 12, 42, 101, 130] 
 
*/

 



answered Dec 8, 2024 by avibootz

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