Question

How to use trunc() function to round N toward zero, and get the nearest integer not greater in magnitude than N in C++

Answer 1

#include <iostream>
#include <cmath>

using namespace std;

int main()
{
	cout << "trunc(3.3) = " << trunc(3.3) << endl;
	cout << "trunc(3.5) = " << trunc(3.5) << endl;
	cout << "trunc(4.5) = " << trunc(4.5) << endl;
	cout << "trunc(4.6) = " << trunc(4.6) << endl;
	cout << "trunc(-3.3) = " << trunc(-3.3) << endl;
	cout << "trunc(-3.5) = " << trunc(-3.5) << endl;
	cout << "trunc(-4.5) = " << trunc(-4.5) << endl;
	cout << "trunc(-4.6) = " << trunc(-4.6) << endl;
	cout << "trunc(-0.0) = " << trunc(-0.0) << endl;

	return 0;
}

/*
run:

trunc(3.3) = 3
trunc(3.5) = 3
trunc(4.5) = 4
trunc(4.6) = 4
trunc(-3.3) = -3
trunc(-3.5) = -3
trunc(-4.5) = -4
trunc(-4.6) = -4
trunc(-0.0) = -0

*/

 

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