Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,845 questions

51,766 answers

573 users

How to use round() function to round to nearest integer in floating-point format, halfway cases away from zero in C

1 Answer

0 votes
#include <stdio.h>     
#include <math.h>
 
int main(int argc, char **argv)
{   
	printf("round(3.3) = %.1f\n", round(3.3));
    printf("round(3.5) = %.1f\n", round(3.5));
    printf("round(4.5) = %.1f\n", round(4.5));    
    printf("round(4.6) = %.1f\n", round(4.6));
    printf("round(-3.3) = %.1f\n", round(-3.3));
    printf("round(-3.5) = %.1f\n", round(-3.5));
    printf("round(-4.5) = %.1f\n", round(-4.5));    
    printf("round(-4.6) = %.1f\n", round(-4.6));
  
    return 0;
}
 
/*
run:
   
round(3.3) = 3.0
round(3.5) = 4.0
round(4.5) = 5.0
round(4.6) = 5.0
round(-3.3) = -3.0
round(-3.5) = -4.0
round(-4.5) = -5.0
round(-4.6) = -5.0

*/

 



answered Mar 29, 2016 by avibootz
...